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Hello, the jack in the trunk is a scissor jack I drew my free body diagram and got that f=mg/2cos15°. To get the jack out of the trunk, the scissor jack needs to be closed/compressed a little

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If you look in the trunk around the spare tire you should find a small tool bag The question is what is the applied force required to lift the 450 kg mass It contains a lug wrench and it contains a tool to raise and lower the jack (it has a hooked end).

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I’d like to change the oil in my car by myself

I want to buy car ramps, but some people say a car jack is better I’d rather have the opinion of those with experience, so, which one is safer to use? Designing a car jack involves considering the lifting capacity, user force, and mechanical advantage required for effective operation Safety features, such as a properly designed top plate with lips to prevent slipping, are crucial

The project should also account. The complete weight of whatever part of the car rests on the ratchet bar and its weight is subsequently held in place by that skinny pin In other words, in the past i had half of the cars weight rest on two skinny pins, one in each jack Thinking back, it sounds like attempted suicide to use these types of jacks on cars.

To find the normal force of a car jack lifting a car, the discussion focuses on calculating the distribution of weight between the jack and the wheels based on torque and force equations

The car's center of mass and the distances from the wheels are critical in setting up the equations Participants emphasize the importance of equilibrium, noting that both net force and net torque must equal. If the car fell off the jack twice there is either something wrong with the jack or the method being used to raise the car Any damage to the car can be easily and readily repaired

Any damage to your husband resulting from the car falling in him is not as easily repaired. Yesterday we found a new type of car jacks which is a hydraulic bottle jack but with a screw instead of the bumb just like the scissor jack In this case how can we convert the pursuer and force to the torque needed from the motor ? Should the truck be put “on blocks,” and how do you do this?

Hi, i am designing an electrical car jack, my question is before i choose the proper electric motor, how do i calculate the torque require to lift the load, let say 100kg.

The problem is a simple scissors jack has lifted a 450 kg car and the angle of the arms of the jack are 15° as seen in the attached drawing 2